Let the ship start at O and sail due East to A and then due North to B.
Using Pythagoras Theorem we have,
OB2=OA2+AB2 [1 Mark]
OB2=142+482
OB2=(2×7)2+(2×24)2
OB2=22(72+242)
OB2=22(252).....(7−24−25 Pythagoras Triplet)
OB=50 cm [1 Mark]
A man walks 8 km due North, then 5 km to East and 4 km to North. How far is he from the starting point?