A ship travels downstream from point A to point B in two hours and upstream in three hours. Then the time that it will take a log of wood to cover the distance from A to point B is :

12 h

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7 h

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5 h

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1 h

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Solution

The correct option is A $12 h$
$\begin{matrix} V = \frac{5}{t} \frac{x}{V_{5} + V_{w}} = 2, \frac{x}{V_{5} + V_{w}} = 3, d i s t a n c e = x D i v i d i n g \frac{x}{V_{5} + V_{w}} + \frac{V_{5} - V_{w}}{x} = \frac{2}{3} V_{5} = 5 V_{w} \frac{x}{5 V_{w} + V_{w}} = 2 \frac{x}{6 V_{w}} = 2 \frac{x}{V_{w}} = 12 h \end{matrix}$

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A ship travels downstream from point A to point B in two hours and upstream in three hours. Then the time that it will take a log of wood to cover the distance from A to point B is :

The correct option is A 12hV=5txV5+Vw=2,xV5+Vw=3,distance=xDividingxV5+Vw+V5−Vwx=23V5=5Vwx5Vw+Vw=2x6Vw=2xVw=12h