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Standard VII

Mathematics

Integers

A shop keeper...

Question

A shop keeper earns a profit of ₹ $(+ 25)$ per bag and incurs a loss of ₹ $(- 15)$ per water bottle. If the following table shows the sale of 2 days then, find the total profit/loss.

Bag Water Bottle

Day 1 8 15

Day 2 2 15

Profit of ₹200

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Loss of ₹ 200

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Profit of ₹ 450

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Loss of ₹ 450

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Solution

The correct option is B Loss of ₹ 200
Profit earned on bags in 2 days = $[8 + 2] \times (+ 25) = 10 \times (+ 25) = (+ 250)$
Loss incurred on water bottles in 2 days = $[15 + 15] \times (- 15) = 30 \times (- 15) = (- 450)$
$∴$ Total Profit/Loss = (+250) + (-450)
= ₹(-200)
Hence the shop keeper had a loss of ₹ 200.

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A shop keeper earns a profit of ₹(+25) per bag and incurs a loss of ₹(−15) per water bottle. If the following table shows the sale of 2 days then, find the total profit/loss. Bag Water Bottle Day 1 8 15 Day 2 2 15

The correct option is B Loss of ₹ 200Profit earned on bags in 2 days = [8+2]×(+25)=10×(+25)=(+250) Loss incurred on water bottles in 2 days = [15+15]×(−15)=30×(−15)=(−450) ∴ Total Profit/Loss = (+250) + (-450) = ₹(-200) Hence the shop keeper had a loss of ₹ 200.

A shop keeper earns a profit of ₹ $(+ 25)$ per bag and incurs a loss of ₹ $(- 15)$ per water bottle. If the following table shows the sale of 2 days then, find the total profit/loss.

Bag Water Bottle

Day 1 8 15

Day 2 2 15