A shopkeeper purchased $392 k g 500 g$ of orange. Later on, he found that $56 k g 460 g$ of oranges were rotten. Find the quantity of oranges in good condition.

330 k g 400 g

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336 k g 4 g

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336 k g 40 g

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33.6 k g 40 g

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Solution

The correct option is C $336 k g 40 g$
Quantity of oranges in good condition $= (392.500 - 56.460) ㎏$
$= 336.040 ℊ \Rightarrow$ $336$ ㎏ $40$ gm

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