A shopkeeper sold $55.050 kg$ of wheat on Monday, on Tuesday he sold $72.500 kg$ of rice and on Wednesday he sold $63.450 kg$ of rice. How much rice in all did the shopkeeper sell?

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Solution

Amount of wheat sold on Monday = $55.050 kg$
Amount of wheat sold on Tuesday = $72.500 kg$
Amount of wheat sold on Wednesday = $63.450 kg$
Total amount of wheat sold in all three days = $(55.050 + 72.500 + 63.450) kg = 191 kg$
Hence, the shopkeeper sold $191 kg$ wheat in all the three days.

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A shopkeeper sold 55.050kg of wheat on Monday, on Tuesday he sold 72.500kg of rice and on Wednesday he sold 63.450kg of rice. How much rice in all did the shopkeeper sell?

Amount of wheat sold on Monday = 55.050kgAmount of wheat sold on Tuesday = 72.500kgAmount of wheat sold on Wednesday = 63.450kgTotal amount of wheat sold in all three days = (55.050+72.500+63.450)kg=191kgHence, the shopkeeper sold 191kg wheat in all the three days.

A shopkeeper sold $55.050 kg$ of wheat on Monday, on Tuesday he sold $72.500 kg$ of rice and on Wednesday he sold $63.450 kg$ of rice. How much rice in all did the shopkeeper sell?

Amount of wheat sold on Monday = $55.050 kg$
Amount of wheat sold on Tuesday = $72.500 kg$
Amount of wheat sold on Wednesday = $63.450 kg$
Total amount of wheat sold in all three days = $(55.050 + 72.500 + 63.450) kg = 191 kg$
Hence, the shopkeeper sold $191 kg$ wheat in all the three days.