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A short electric dipole has a moment of 16×109 Cm. The electric potential due to the dipole at a point at distance of 0.6 m from the centre of the dipole, situates on a line making an angle of 60 with the dipole axis is

A
Zero
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B
50 V
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C
200 V
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D
400 V
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Solution

The correct option is C 200 V
Given dipole moment of short electric dipole,

|P|=16×109 Cmdistance r=0.6 m andθ=60cos60=12

Electric potential, V=KPcosθr2

V=9×109×16×109×12(0.6)2

=9×836×102=200 V


<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (c) is the correct answer.

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