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Question

# A short electric dipole has a moment of 16×10−9 Cm. The electric potential due to the dipole at a point at distance of 0.6 m from the centre of the dipole, situates on a line making an angle of 60∘ with the dipole axis is

A
Zero
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B
50 V
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C
200 V
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D
400 V
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Solution

## The correct option is C 200 V Given dipole moment of short electric dipole, |→P|=16×10−9 Cmdistance r=0.6 m andθ=60∘⇒cos60∘=12 Electric potential, V=KPcosθr2 V=9×109×16×10−9×12(0.6)2 =9×836×10−2=200 V <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (c) is the correct answer.

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