A shot is fired from a point at a distance of $200 m$ from the foot of a tower $100 m$ high so that it just passes over it horizontally. The direction of shot with horizontal is

30^{\circ}

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45^{\circ}

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60^{\circ}

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70^{\circ}

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Solution

The correct option is B $45^{\circ}$
Given:
$H = 100 m, R = 2 \times 200 = 400 m$
$tan θ = \frac{4 H}{R} \Rightarrow tan θ = \frac{4 \times 100}{400} = 1$
$\Rightarrow θ = 45^{\circ} [∵ \frac{H}{R} = \frac{tan θ}{4}]$ .

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A shot is fired from a point at a distance of 200 m from the foot of a tower 100 m high so that it just passes over it horizontally. The direction of shot with horizontal is

The correct option is B 45∘Given:H=100 m,R=2×200=400 mtanθ=4HR⇒tanθ=4×100400=1⇒θ=45∘[∵HR=tanθ4].

A shot is fired from a point at a distance of $200 m$ from the foot of a tower $100 m$ high so that it just passes over it horizontally. The direction of shot with horizontal is

The correct option is B $45^{\circ}$
Given:
$H = 100 m, R = 2 \times 200 = 400 m$
$tan θ = \frac{4 H}{R} \Rightarrow tan θ = \frac{4 \times 100}{400} = 1$
$\Rightarrow θ = 45^{\circ} [∵ \frac{H}{R} = \frac{tan θ}{4}]$ .