Question

A side and face cutter 125 mm diameter has 10 teeth. If operates at a cutting speed of 14 m/min with a table traverse 100 mm/min the feed per tooth of the cutter is

• A. 10 mm
• B. 2.86 mm
• C. 0.286 mm
• D. 0.8 mm

Answer 1

The correct option is C 0.286 mm

$N=\frac{1000\times 14}{\pi \times 125}=35.67$

Feed per tooth = $f_t$

$=\frac{f_m}{Nz}=\frac{100}{35.67\times 10}=0.25\text{mm/tooth}$