A signal mt-3cos-1t-4cos-2t is FM modulated- The B-W of the signal will be- in kHz-1-6-103rad- -2-4-103rad- -kf-10kHz-Volt-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Distance

A signal mt=3...

Question

A signal $m (t) = 3 cos ω_{1} t + 4 cos ω_{2} t$ is FM modulated. The B.W of the signal will be: (in kHz) $[ω_{1} = 6 π \times 10^{3} r a d / sec ω_{2} = 4 π \times 10^{3} r a d / sec], k_{f} = 10 k H z / V o l t]$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

146

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 146
(d)
$B . W . = 2 (Δ f + f_{m})$

$Δ f = {k_{f} m (t) ∣ ∣}_{max} = 10 [3 + 4] = 70 k H z$

$B . W = 2 [70 k + 3 k] = 146 k H$

Suggest Corrections

Similar questions

Q. A message signal m(t) = sinc(1000t) V is applied to an FM modulator, whose frequency Sensitivity is

k_{f} = 1 k H z / V

. The modulation index (or deviation ratio) of the resultant FM signal will be

Q. A signal m(t) is applied to a FM modulator with frequency modulation constant

K_{f} = 24 k H z / V .

If the Fourier Transform of m(t) is

M (ω) = S a (2 ω)

then which of the following statement(s) is/are correct?

Consider the message signal shown in the figure below:

If this message signal m(t) is applied to an FM modulator whose frequency sensitivity is $k_{f} = 0.5 H z / V$ , then the maximum phase deviation of the resultant FM signal will be _____ radians.

Q. An Am signal is modulated by 50% such that FOM of AM. becomes equal to the Figure of ment (FOM) of FM signal is FM modulated. The modulation index of FM will be _________

Q. The modulation index of an

F M

carrier having a carrier swing of

200 k H z

and a modulating signal

10 k H z

Join BYJU'S Learning Program

A signal m(t)=3cosω1t+4cosω2t is FM modulated. The B.W of the signal will be: (in kHz)[ω1=6π×103rad/secω2=4π×103rad/sec],kf=10kHz/Volt]

The correct option is B 146(d) B.W.=2(Δf+fm) Δf=kfm(t)∣∣max=10[3+4]=70kHz B.W=2[70k+3k]=146kH

A signal $m (t) = 3 cos ω_{1} t + 4 cos ω_{2} t$ is FM modulated. The B.W of the signal will be: (in kHz) $[ω_{1} = 6 π \times 10^{3} r a d / sec ω_{2} = 4 π \times 10^{3} r a d / sec], k_{f} = 10 k H z / V o l t]$

The correct option is B 146
(d)
$B . W . = 2 (Δ f + f_{m})$

$Δ f = {k_{f} m (t) ∣ ∣}_{max} = 10 [3 + 4] = 70 k H z$

$B . W = 2 [70 k + 3 k] = 146 k H$