A simple harmonic motion of a spring-block system has an amplitude A & time period T. Consider x=0 for equilibrium position. The time required by the block to travel from x=A to x=A2 is -
Time required to travel from x = A to x = 0 is T4 & time required to travel from x = 0 to x = A2 is obtained from
y=A sin(2πT)t
A2=A sin(2πT)t
⇒sin(π6)=sin(2πT)t
⇒t=T12
⇒ Time required to travel from x=A to x=A2 will be
T4−T12=T6