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Question

A simple harmonic motion of a spring-block system has an amplitude A & time period T. Consider x=0 for equilibrium position. The time required by the block to travel from x=A to x=A2 is -


A

T6

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B

T4

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C

T3

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D

T2

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Solution

The correct option is A

T6


Time required to travel from x = A to x = 0 is T4 & time required to travel from x = 0 to x = A2 is obtained from

y=A sin(2πT)t

A2=A sin(2πT)t

sin(π6)=sin(2πT)t

t=T12

Time required to travel from x=A to x=A2 will be

T4T12=T6


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