A simple harmonic oscillator is of mass 0.100 kg. It is oscillating with a frequency of 5πHz. If its amplitude of vibration is 5 cm, the force acting on the particle at its extreme position is
A
2 N
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B
1.5 N
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C
1 N
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D
0.5 N
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Solution
The correct option is D 0.5 N F=mω2A ω=2πf=10rad/sec F=0.1×100×5100 =0.5N