CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A simple pendulum has time period T1. The point of suspension is now moved upward according to the relation y=Kt2,(K=1m/s2) where y is the vertical displacement. The time period now becomes T2. The ratio of

T21T22 is : (g=10m/s2)


A

6/5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

5/6

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

4/5

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

6/5


y=Kt2

d2ydt2=2K

or ay=2m/s2 (as k=1m/s2)

T1=2πlg

And T2=2πlg+ay

T21T22=g+ayg

=10+210=65

correct answer is (a)


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Simple Pendulum
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon