A simply supported beam has a span of 12 m. A udl of 30 kN/m of 4 m length crosses the beam from left to right. The maximum bending moment at a section 5 m from left (in kN - m, round off to two decimals) is
291
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Solution
The correct option is A 291
Bending moment at C will be maximum when load position is such that the section divides the load in the same ratio as it divides the span. x4−x=57 7x=20−5x x=2012=1.667m ∑MB=0 RA×12=30×4×(7+1.667−2) RA=66.67kN ∴MC=66.67×5−30×1.66722=291.67kN−m