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Question

A sinusoidal voltage V=200sin314t is applied to a 10Ω resistor. Find power dissipated as heat.

A
500W
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B
1000W
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C
2000W
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D
3000W
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Solution

The correct option is C 2000W
Answer: C
General sinusoidal voltage variation is given by:
V=V0sin(ωt)
Here, in this equation V0 is peak voltage.
So, on comparing both equation we get:
V0=200V,ω=314
Relation between rms voltage and peak voltage is:
Vrms=V02=2002=141.4V
Relation between rms current and peak current is:
Irms=VrmsR=141.410=14.14A
P=Vrms×Irms=141.4×14.14=1999.396W

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