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Question

# A skydiver with mass of 60 kg is moving at a constant speed of 20 ms−1 . Rate of work done by gravity is _____. Take g=10 ms−2

A
6 kW
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B
8 kW
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C
12 kW
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D
6 kW
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Solution

## The correct option is C 12 kWGiven: Mass of skydiver m=60 kg, Constant velocity = v = 20 ms−1 Acceleration due to gravity g=10 ms−2 Rate of work done by gravity = work donetime Force applied by gravity F=mg=60×10=600 N. Let the skydiver travel x metres in t seconds. Work done in t seconds = Force × Displacement =(60×10×x) J So, power =(60×10×x)t = 60×10×xt = 60×10× v = 60×10×20 = 12000 W = 12 kW

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