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Question

A slab of glass of thickness of 3 units and refractive index √3 is surrounded by vacuum and is placed as shown. A light ray is incident at the point (2,5√3) as shown. The point where the ray will cut the X− axis is:

A
(6,0)
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B
(5+3,0)
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C
(9,0)
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D
(8,0)
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Solution

The correct option is C (9,0)Given thickness of slab BC=3 units coordinate of B is (2,5√3) ∴CE=5√3 Applying Snell's law at B, 1sin i=μsin r 1sin 60∘=√3sin r √32=√3sin r ∴r=30∘ From ΔBCD CD=BCtanr=3tan 30∘=√3 ∴DE=CE−CD=[5√3−√3]=4√3 From triangle DEF ∴EF=DEcot60∘=4√3cot 60∘=4 ∴ Coordinate of point E=(3+2+4,0)=(9,0)

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