Question

A slightly polar molecule AB has a dipole moment of $0.24D$. If bond-length is $1\mathring{A}$, ionic character is (%):

Answer 1

1D$=3.336\times {10}^{-30}C.m$
0.24$=0.24\times 3.336\times {10}^{-30}C.m$
$0.24\times 3.336\times {10}^{-30}C.m=$$charge\times distance$
$0.24\times 3.336\times {10}^{-30}C.m=charge\times {10}^{-10}$
charge$=0.24\times 3.336\times {10}^{-20}C$
charge$=\frac{0.8006\times {10}^{-20}}{1.602\times {10}^{-19}}$
charge$=0.05e$
ionic character$=0.05\times 100$
ionic character$=5$