A slow neutron strikes a nucleus of $_{92}^{235} U$ splitting it into lighter nuclei of $_{56}^{141} B a$ and $_{36}^{92} K r$ along with three neutrons. The energy released in this reaction is :
(The masses of Uranium, Barium and Krypton in this reaction are $235.043933, 140.917700$ and $91.895400 a m u$ respectively. The mass of a neutron is $1.008665 a m u$ )

198.87 M e V

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156.9 M e V

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186.9 M e V

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196.9 M e V

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Solution

The correct option is A $198.87 M e V$
$_{92}^{235} U +^{1} n \to_{56}^{141} B a +_{36}^{92} K r + 3^{1} n$
$Δ m = [235.043933 - 140.9177 - 91.8954 - 2 (1.008665)]$
$= 0.213503 a m u$
$E = 0.21503 \times 931.5 M e V$
$= 198.87 M e V$

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Similar questions

Q. Assertion :The splitting of atomic nuclei releases enormous energy Reason: When a single free neutron strikes the nucleus of an atom of fissile (radioactive) material like uranium 235 or plutonium 239, it usually knocks two or three more neutrons free.

___ is the phenomenon of splitting up of a heavy nucleus, on bombardment with slow speed neutrons, into fragments of comparable mass, with the releasing of a large amount of energy.

Q. The splitting of a heavy nucleus with neutron into two smaller nuclei along with the release of a large amount of energy is known as ______.

Q. When a Uranium isotope is bombarded with a thermal neutron, it generates

\begin{matrix} 14156 \end{matrix} Ba

, three neutrons and

Fill in the blanks:-

The nucleus of a _______ atom (such as uranium, plutonium or thorium),

when bombarded with__________ neutrons, can be split apart into lighter

nuclei.

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The correct option is A 198.87 MeV23592U+1n→14156Ba+9236Kr+31nΔm=[235.043933−140.9177−91.8954−2(1.008665)] =0.213503 amuE=0.21503×931.5MeV =198.87 MeV

The correct option is A $198.87 M e V$
$_{92}^{235} U +^{1} n \to_{56}^{141} B a +_{36}^{92} K r + 3^{1} n$
$Δ m = [235.043933 - 140.9177 - 91.8954 - 2 (1.008665)]$
$= 0.213503 a m u$
$E = 0.21503 \times 931.5 M e V$
$= 198.87 M e V$