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Standard VI

Physics

Volume of Liquids

A small hole ...

Question

A small hole is made at a height of $h = \frac{1}{2} m$ from the bottom of a cylindrical water tank and at a depth of $h = 2 m$ from the upper level of water in the tank. The distance, where the water emerging from the hole strikes the ground, is:

22 m

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1 m

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2 m

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None of these.

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Solution

The correct option is C $2 m$
Range of water coming out = 2 $\sqrt{h (H - h)}$
given h = $\frac{1}{2}$ m & H-h = 2m.
So Range = 2 $\sqrt{\frac{1}{2} \times 2}$ = 2m

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A small hole is made at a height of h=12m from the bottom of a cylindrical water tank and at a depth of h=2m from the upper level of water in the tank. The distance, where the water emerging from the hole strikes the ground, is:

The correct option is C 2mRange of water coming out = 2√h(H−h)given h = 12m & H-h = 2m.So Range = 2√12×2 = 2m

A small hole is made at a height of $h = \frac{1}{2} m$ from the bottom of a cylindrical water tank and at a depth of $h = 2 m$ from the upper level of water in the tank. The distance, where the water emerging from the hole strikes the ground, is:

The correct option is C $2 m$
Range of water coming out = 2 $\sqrt{h (H - h)}$
given h = $\frac{1}{2}$ m & H-h = 2m.
So Range = 2 $\sqrt{\frac{1}{2} \times 2}$ = 2m