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Question

A small hole of area of cross-section 2 mm2 is present near the bottom of a fully filled open tank of height 2 m. Taking g=10 m/s2 , the rate of flow of water through the open hole would be nearly

A
12.6×106 m3/s
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B
8.9×106 m3/s
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C
2.23×106 m3/s
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D
6.4×106 m3/s
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Solution

The correct option is A 12.6×106 m3/s
Velocity of efflux, v =2gh
Volume flow rate, Q = Av = A2gh =(2×106)(2×10×2)1/2 =410×106 m3/s 12.6×106 m3/s

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