A small quantity of gaseous NH3 and HBr are introduced simultaneously into the opposite ends of an open tube that is 1m long. Calculate the distance of the white solid NH4Br formed from the end that was used to introduce NH3.
68.55 cm
By Graham's law of diffusion:
rNH3rHBr=√8117=2.18
Thus , NH3 travels 2.18 times faster than HBr.In other words,NH3 will travel 2.18 cm in the same time in which HBr travels 1cm.Given that the length of the tube=100cm.
Therefore, distance travelled in the tube by
NH3=2.18⟮2.18+1⟯×100 = 68.55 cm
Thus , NH4Br will first appear at a distance of 68.55 cm from NH3 end.
Required distance = 68.55 cm from NH3 end.