A small steel ball falls through a syrup at a constant speed of $10 c m / s e c .$ If the steel ball is pulled upwards with a force equal to twice its effective weight; how fast will it move upwards?

10 c m / s e c

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20 c m / s e c

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5 c m / s e c

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0 c m / s e c

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Solution

The correct option is A $10 c m / s e c$
When the ball is falling down, force of buoyancy and weight balance each other. as it moves at constant speed.
If the ball is pulled at double its effective weight, then bouyant force and weight will together balance it and it moves at constant speed of $10 c m s^{- 1}$ .

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A small steel ball falls through a syrup at a constant speed of 10cm/sec. If the steel ball is pulled upwards with a force equal to twice its effective weight; how fast will it move upwards?

The correct option is A 10cm/secWhen the ball is falling down, force of buoyancy and weight balance each other. as it moves at constant speed.If the ball is pulled at double its effective weight, then bouyant force and weight will together balance it and it moves at constant speed of 10cms−1.

A small steel ball falls through a syrup at a constant speed of $10 c m / s e c .$ If the steel ball is pulled upwards with a force equal to twice its effective weight; how fast will it move upwards?