The correct option is D Energy of the photon is approximaltely 2.07 eV
Given: wavelength = 600 nm = 600×10−9 m = 6000 ∘A
We know, ν=cλ
where c = speed of light
ν = frequency of the light
λ = wavelength of the radiation
So, ν = 3×108600×10−9 = 5×1014 s−1
E = 12400 eV ∘A6000 ∘A
E = 2.07 eV