Question

A soft drink is available in two packs−
(i) a tin can with a rectangular base of length 5 cm and width 4 cm, having a height of 15 cm
(ii) a plastic cylinder with a circular base of diameter 7 cm and height 10 cm. Which container has greater capacity and by how much?

$[Assume\pi =\frac{22}{7}]$

Answer 1

The tin can will be cuboidal in shape while the plastic cylinder will be cylindrical in shape.

Length (l) of the tin can = 5 cm

Breadth (b) of the tin can = 4 cm

Height (h) of the tin can = 15 cm
Capacity of the tin can $=l\times b\times h=(5\times 4\times 15)c{m}^3$

$=300c{m}^3$

Radius (r) of the circular end of plastic cylinder $=\left(\frac{7}{2}\right)cm=3.5cm$

Height (H) of the plastic cylinder = 10 cm
Capacity of the plastic cylinder $=\pi r^{2}H$

$=[\frac{22}{7}\times (3.5{)}^2\times 10]c{m}^3=(11\times 35)c{m}^3=385c{m}^3$

Therefore, plastic cylinder has the greater capacity.

Difference in the capacity $=(385-300)c{m}^3=85c{m}^3$