Question

A soft drink is available in two packs-
(i) a tin can with a rectangular base of length $5$ cm and width $4$ cm, having a height of $15$ cm
(ii) a plastic cylinder with circular base of diameter $7$ cm and height $10$ cm.
Which container has greater capacity and by how much?

Answer 1

Given:

Length $=5$cm [Tin can]

Breadth $=4$cm
Height $=15$cm

$\Rightarrow$Capacity volume

$=l\times b\times \times h=5\times 4\times 15$

$=300$cm${}^3$

$\Rightarrow$Radius of cylinder $=\frac{7}{2}=3.5$cm, $H=10$cm

$\Rightarrow$Capacity $=\pi R^{2}H=(\frac{22}{7}\times {\left(3.5\right)}^2\times 10)$cm${}^3=385c{m}^3$

$\Rightarrow$Cylinder has more capacity by

$=(385-300)$cm${}^3$
$=85$cm${}^3$