A solid block of volume V and density -5 floats on a liquid of density - How much force should be applied over the block to completely submerge it under water- Given- g - 10 m-s2- - 103 kg-m3- V - 10 m3

A solid weighs $50 N$ in the air and $45 N$ when completely immersed in water. Density of water $ρ$ = $1000 k g / m^{3}$ . Calculate the volume of the solid.

(Take acceleration due to gravity = $10 m / s^{2}$ )

Q. A block of wood floats in water with

{\frac{4}{5}}^{th}

of its volume submerged but in another liquid, it floats fully submerged. The density of the unknown liquid is (in

{kg/m}^{3}

)

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A solid block of volume V and density ρ5 floats on a liquid of density ρ. How much force should be applied over the block to completely submerge it under water? (Given: g=10 m/s2,ρ=103 kg/m3,V=10 m3)

The correct option is B 8×104 NApplied force + True weight = Upthrust Applied force = Upthrust – True weight =ρVg−(15ρ)Vg =45ρVg =45(103)(10)(10) =8×104 N

A solid block of volume $V$ and density $\frac{ρ}{5}$ floats on a liquid of density $ρ$ . How much force should be applied over the block to completely submerge it under water? (Given: $g = 10 {m/s}^{2}, ρ = 10^{3} {kg/m}^{3}, V = 10 m^{3})$

The correct option is B $8 \times 10^{4} N$
Applied force + True weight = Upthrust
Applied force = Upthrust – True weight
$= ρ V g - (\frac{1}{5} ρ) V g$
$= \frac{4}{5} ρ V g$
$= \frac{4}{5} (10^{3}) (10) (10)$
$= 8 \times 10^{4} N$