Question

a solid body of weight 50N is immersed in water. if the weight of it when immersed in water is 45N 1) what is the relative density of the body. 2) what is the density of the body.

Answer 1

Dear Student,

$$\begin{gathered} \left(1\right)\mathrm{Relative}\mathrm{density}\mathrm{of}\mathrm{body}=\frac{\mathrm{weight}\mathrm{in}\mathrm{air}}{\mathrm{loss}\mathrm{of}\mathrm{weight}\mathrm{in}\mathrm{water}} \\ \mathrm{Relative}\mathrm{density}\mathrm{of}\mathrm{body}=\frac{50}{50-45} \\ \mathrm{Relative}\mathrm{density}\mathrm{of}\mathrm{body}=\frac{50}{5}=10 \\ \left(2\right)\mathrm{Relative}\mathrm{density}=\frac{\mathrm{density}\mathrm{of}\mathrm{body}}{\mathrm{density}\mathrm{of}\mathrm{water}} \\ 10=\frac{\mathrm{density}\mathrm{of}\mathrm{body}}{1}......\left[\mathrm{density}\mathrm{of}\mathrm{water}=1\mathrm{g}/{\mathrm{cm}}^3\right] \\ \mathrm{density}\mathrm{of}\mathrm{body}=10\mathrm{g}/{\mathrm{cm}}^3 \end{gathered}$$