A solid element reacts with insufficient oxygen and the reaction shows no change in volume of gaseous phase. If vapour density of gaseous product is $32$ , the equivalent mass of element would be :

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Solution

The correct option is C 8
Molar mass of gaseous product $= 2 \times v a p o u r d e n s i t y = 64 g {m o l}^{- 1}$
So, gas is $S O_{2}$ .
$S + O_{2} (g) \to S O_{2} (g); Δ V = 0$
So, eq. mass of S = $\frac{32}{4} = 8$

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A solid element reacts with insufficient oxygen and the reaction shows no change in volume of gaseous phase. If vapour density of gaseous product is 32, the equivalent mass of element would be :

The correct option is C 8Molar mass of gaseous product =2×vapour density=64 g mol−1So, gas is SO2.S+O2(g)→SO2(g); ΔV=0So, eq. mass of S =324=8

A solid element reacts with insufficient oxygen and the reaction shows no change in volume of gaseous phase. If vapour density of gaseous product is $32$ , the equivalent mass of element would be :

The correct option is C 8
Molar mass of gaseous product $= 2 \times v a p o u r d e n s i t y = 64 g {m o l}^{- 1}$
So, gas is $S O_{2}$ .
$S + O_{2} (g) \to S O_{2} (g); Δ V = 0$
So, eq. mass of S = $\frac{32}{4} = 8$