The density of a gaseous element is 5 times that of oxygen under similar conditions. If the molecule of the element is triatomic, what will be its atomic mass ?

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Solution

Molecular mass of oxygen = 32
Vapour density of oxygen $= \frac{32}{2} = 16$
Thus, vapour density of the gaseous element $= 16 \times 5 = 80$
Molecular mass of the gaseous element $= 80 \times 2 = 160$
As the molecule is triatomic, its atomic mass $= \frac{M o l . m a s s}{A t o m i c i t y}$
$= \frac{160}{3} = 53.33$

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The density of a gaseous element is 5 times that of oxygen under similar conditions. If the molecule of the element is triatomic, what will be its atomic mass ?

Molecular mass of oxygen = 32 Vapour density of oxygen =322=16Thus, vapour density of the gaseous element =16×5=80 Molecular mass of the gaseous element =80×2=160 As the molecule is triatomic, its atomic mass =Mol.massAtomicity=1603=53.33