A solid has a structure in which W atoms are located at the corners of a cubic lattice, O atoms at the center of edges and Na atom at the center of the cube. The formula for the compound is:

N a W O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N a W O_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N a_{2} W O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N a W O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $N a W O_{3}$
No of atoms of W = $\frac{1}{8} \times 8 = 1$

No of atoms of Na = $1 \times 1 = 1$

No of atoms of O = $\frac{1}{4} \times 12 = 3$

Therefore, the compound is $N a W O_{3}$ .

Hence, option B is correct.

Suggest Corrections

Similar questions

Q. A solid has a structure in which '

W

' atoms are located at the corners of a cubic lattice '

O

' atom at the center of the edge and

N a

atoms at the center of the cube. The formula for the compound is:

A solid has a structure in which W atoms are located at the corners of a cubic lattice, O atoms are at the center of face edges and Na atoms are at the center of the cube. The formula of the compound is:

Q. A solid has a structure in which W atoms are located at the corners of the cubic lattice, O atoms at the center of the edges and Na atom at the centre of the cube. The formula of the compound is

Q. A solid has a structure in which W atoms are located at the corners of edges, O atoms are at the center of face edges and Na atom at the center of the cube. The formula of the compound is:

A solid has a structure in which 'W' atoms are located at the corners of a cubic lattice 'O' atoms at the centre of edges and 'Na' atoms at the centre of the cube. The formula for the compound is

[KCET 1996]

Join BYJU'S Learning Program

A solid has a structure in which W atoms are located at the corners of a cubic lattice, O atoms at the center of edges and Na atom at the center of the cube. The formula for the compound is:

The correct option is B NaWO3No of atoms of W = 18×8=1No of atoms of Na =1×1=1No of atoms of O = 14×12=3Therefore, the compound is NaWO3.Hence, option B is correct.

The correct option is B $N a W O_{3}$
No of atoms of W = $\frac{1}{8} \times 8 = 1$

No of atoms of Na = $1 \times 1 = 1$

No of atoms of O = $\frac{1}{4} \times 12 = 3$

Therefore, the compound is $N a W O_{3}$ .

Hence, option B is correct.