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Question

A solid iron cuboidal block of dimensions 4.4 m×2.6 m×1 m is recasted into a hollow cylindrical pipe of internal radius 30 cm and thickness 5 cm. The length of the pipe is ________.



Your Answer
A

11.2 cm

Your Answer
B

11.2 m

Your Answer
C

112 cm

Correct Answer
D

112 m


Solution

The correct option is D

112 m


Since the pipe is obtained from the block, volume of both objects will be exactly equal to each other.

Volume of cuboid
=l×b×h

Volume of cylinder

=π((Ro)2(Ri)2)×h,

where Ro and Ri indicate outside radius and inside radius respectively.

So,
 
440×260×100=π×(352302)×h

[NOTE : 1 m=100 cm]

440×260×100=π×(35+30)(3530)×h
440×260×100=227×325 h

h=440 × 260 × 100 × 722×325

 h=11200 cm

h=112 m

Hence, the length of the pipe is 112 m.

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