Question

A solid is in the form of a right circular cylinder with a hemisphere at one end and a cone at the other end. The radius of the common base is 8cm. and the heights of the cylindrical and conical portions are 10cm and 6cm respectively. Find the total surface area of the solid. (Use $\pi$= 3.14).

• A. undefined
• B. undefined
• C. undefined
• D. undefined

Answer 1

Total surface area = Curved surface area of cone + curved surface area of cylinder + curved surface are of hemisphere
Start height of cone $=\sqrt{5^3+8^2}$
= 10
$=\pi rl+2\pi rh+2\pi r^2=\pi r[2+2h+r]=3.14\times 8\times [10+20+16]=3.19\times 8\times 46=\mathrm{1.155.52}c{m}^2$