A solid is made of two elements X and Z. The atoms Z are in CCP arrangement while the atom X occupy two-third of the tetrahedral sites. What is the formula of the compound?

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X Z_{2}

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X_{4} Z_{3}

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X_{2} Z_{3}

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Solution

The correct option is C $X_{4} Z_{3}$
Tetrahedral sites are double compared to octahedral sites; and X is present in two-third of them

a) So, ratio of X and Z equals $2 \times (\frac{2}{3}) : 1 = 4 : 3$
$\Rightarrow$ formula of the compound = $X_{4} Z_{3}$

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A solid is made of two elements X and Z. The atoms Z are in CCP arrangement while the atom X occupy two-third of the tetrahedral sites. What is the formula of the compound?

The correct option is C X4Z3 Tetrahedral sites are double compared to octahedral sites; and X is present in two-third of them a) So, ratio of X and Z equals 2×(23):1=4:3 ⇒ formula of the compound = X4Z3

The correct option is C $X_{4} Z_{3}$
Tetrahedral sites are double compared to octahedral sites; and X is present in two-third of them

a) So, ratio of X and Z equals $2 \times (\frac{2}{3}) : 1 = 4 : 3$
$\Rightarrow$ formula of the compound = $X_{4} Z_{3}$