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Total Surface Area of a Cuboid

A solid metal...

Question

A solid metallic cuboid of dimensions $(9 m \times 8 m \times 2 m)$ is melted recast into solid cubes of edge $2 m$ . Find the number of cubes so find.

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Solution

Number of cubes so formed $= \frac{V o l u m e o f c u b o i d}{V o l u m e o f c u b e}$

$= \frac{9 \times 8 \times 2}{2 \times 2 \times 2}$

$= 18$ Cubes

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