A solid of density D is floating in a liquid of density d. If v is the volume of solid submerged in the liquid and V is the total volume of the solid, then v/V equals to

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Solution

The correct option is B

Using Archimedes' principle

Buoyant force is equal to weight of water displaced

$F_{B} = d \times v \times g$

$M g = D \times V \times g$

$\Rightarrow d \times v \times g = D \times V \times g$

$\Rightarrow \frac{v}{V} = \frac{D}{d}$

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A solid of density D is floating in a liquid of density d. If v is the volume of solid submerged in the liquid and V is the total volume of the solid, then v/V equals to

The correct option is B Using Archimedes' principle Buoyant force is equal to weight of water displaced FB=d×v×g Mg=D×V×g ⇒d×v×g=D×V×g ⇒vV=Dd

The correct option is B

Using Archimedes' principle

Buoyant force is equal to weight of water displaced

$F_{B} = d \times v \times g$

$M g = D \times V \times g$

$\Rightarrow d \times v \times g = D \times V \times g$

$\Rightarrow \frac{v}{V} = \frac{D}{d}$