A solid of density $D$ is floating in a liquid of density $d$ . If $v$ is the volume of solid submerged in the liquid and $V$ is the total volume of the solid, then $v / V$ equals to

\frac{d}{V}

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\frac{D}{d}

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\frac{D}{(D + d)}

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\frac{D + d}{D}

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Solution

The correct option is A $\frac{D}{d}$
Weight $= V D g$
buoyant force $= v d g$
According to newton's law
Weight $=$ Buoyant force
$V D g = v d g$
$\frac{v}{V} = \frac{D}{d}$

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A solid of density D is floating in a liquid of density d. If v is the volume of solid submerged in the liquid and V is the total volume of the solid, then v/V equals to

The correct option is A DdWeight =VDgbuoyant force =vdgAccording to newton's lawWeight = Buoyant forceVDg=vdgvV=Dd

A solid of density $D$ is floating in a liquid of density $d$ . If $v$ is the volume of solid submerged in the liquid and $V$ is the total volume of the solid, then $v / V$ equals to

The correct option is A $\frac{D}{d}$
Weight $= V D g$
buoyant force $= v d g$
According to newton's law
Weight $=$ Buoyant force
$V D g = v d g$
$\frac{v}{V} = \frac{D}{d}$