The fraction of a floating object of volume $V_{0} a n d d e n s i t y d_{0}$ above the surface of a liquid of density d will be

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Solution

The correct option is C
For the floatation $V_{0} d_{0} g = V_{i n} d g \Rightarrow V_{i n} = V_{0} \frac{d_{0}}{d} ∴ V_{o u t} = V_{0} - V_{i n} = V_{0} - V_{0} \frac{d_{0}}{d} = V_{0} [\frac{d - d_{0}}{d}] \Rightarrow \frac{V_{o u t}}{V_{0}} = \frac{d - d_{0}}{d} .$

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Similar questions

V_{0}

d_{0}

d

What will be the fraction of volume of a floating object of volume V and density d above the surface of a liquid of density D?

D = ∣ ∣ ∣ ∣ \begin{matrix} a_{1} & b_{1} & c_{1} a_{2} & b_{2} & c_{2} a_{3} & b_{3} & c_{3} \end{matrix} ∣ ∣ ∣ ∣

D_{0} = ∣ ∣ ∣ ∣ \begin{matrix} k a_{1} & k b_{1} & k c_{1} k a_{2} & k b_{2} & k c_{2} k a_{3} & k b_{3} & k c_{3} \end{matrix} ∣ ∣ ∣ ∣

D_{0} = k^{3} D

V_{o}

d_{o}

d

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