Question

A solid rectangular piece of iron measures $1.05in\times 70cm\times 1.5cm$. Find the weight of this piece in kilograms if $1c{m}^3$ of iron weighs 8 grams.

Answer 1

Length of iron (l)=1.05 m

=105 cm

breadth (b)=70 cm

and height (h)=1.5 cm

$\therefore$ volume of iron $=l\times b\times h=105\times 70\times 1.5c{m}^3$

$=11025c{m}^3$

weight of $1c{m}^3$ iron =8 gram

$\therefore$ Total weight $=11025\times 8=88200g$

$=\frac{88200}{1000}kg$

=88.2 kg