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Question

# A solid sphere of mass M and radius R having a moment of inertia I about its diameter is recast into a solid disc fo radius r and thickness t. The moment of inertia of the disc about an axis passing the edge and perpendicular to the plane remains I. Then R and r are related as

A
r=215R
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B
r=215R
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C
r=215R
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D
r=215R
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Solution

## The correct option is B r=√215RIAB=25MR2=I (given) (i) IA′B′=IYY′+Mr2=I12Mr2+Mr2 =32Mr2=1 (given) (ii) From Eqs. (i) and (ii), 25MR2=32Mr2⇒ r=2√15R

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