Question

A solid sphere rolls down an inclined plane and its velocity at the bottom is $v_1$. Then same sphere slides down the plane (without friction) and let its velocity at the bottom be $v_2$. Which of the following relation is correct

• A.
• B.
• C.
• D. None of these

Answer 1

The correct option is D None of these

When solid sphere rolls down an inclined plane the velocity at bottom $v_1=\sqrt{\frac{10}{7}gh}$
but, if there is no friction then it slides on inclined plane and the velocity at bottom $v_2=\sqrt{2gh}$
$\therefore \frac{v_1}{v_2}=\sqrt{\frac{5}{7}}.$