A solid weighs $32 g f$ in air and $28.8 g f$ in water. The R.D. of the solid is

8.9

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10

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29.12

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20

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Solution

The correct option is A $10$
Given,
Weight of solid in air $W = 32 g f$
Weight of solid in water $W_{w} = 28.8 g f$
Relative density $= \frac{w e i g h t o f s o l i d i n a i r}{d e c r e a s e i n w e i g h t o f s o l i d i n w a t e r}$

$= \frac{32}{32 - 28.8}$

Relative density $= \frac{32}{3.2} = 10$

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