A solution (5 mL) of an acid X is completely neutralized by y mL of 1 M NaOH. The same volume (y mL) of 1 M NaOH is required to neutralize 10 mL of 0.6 M of H2SO4 completely. The normality (N) of the acid X is
A
1.2
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B
2.4
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C
4.8
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D
0.6
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Solution
The correct option is B 2.4 NaOH (Number of equivalent = H2SO4 (Number of equivalent) (1×1)×y=(0.6×2)×10y=12mL Now, Acid (Number of equivalent) = NaOH(Number of equivalent) N × 5 = (1 × 1) × 12 = 2.4 N