Question

A solution containing $12.0$ % sodium hydroxide by mass has a density of $1.131$ g/mL. What volume of this solution contains $5.00$ mol of NaOH?

• A. 0.0240 L
• B. 1.67 L
• C. 1.47 L
• D. 1.00 L

Answer 1

Answer: (C)

1.47 L

Let the volume of NaOH solution be V mL.
5.00 mol of NaOH corresponds to $5.00\times 40=200.g$ of NaOH.
The density of NaOH is 1.131 g/mL.
V mL of solution corresponds to $1.131Vg$ of solution
The concentration of NaOH is 12.0% by mass.
Hence, $\frac{12.0\times 1.131V}{100}=0.1357Vg$ of NaOH are present.
Thus, $0.1357V=200$
$V=\frac{200}{0.1357}=1473mL=1.47L$
Hence, the volume of the solution is 1.47 L.