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Question

A solution contains 0.1 M H2S and 0.3 M HCl. Calculate the conc. of S2 and HS ions in solution, Given Ka1 and Ka2 for H2S are 107 and 1.3×1013 respectively.

A
1.43×1020M, 3.3×108M
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B
1.43×1010M, 3.3×104M
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C
2.83×1019M, 3.3×108M
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D
1.43×1019M, 1.65×108M
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Solution

The correct option is A 1.43×1020M, 3.3×108M
H2SH++HS; Ka1=107
HSH++S2; Ka2=1.3×1013
HClH++Cl
Due to common ion effect exerted by H+ of HCl, the dissociations of H2S are suppressed and the [H+] in solution is mainly due to HCl.
Ka1=[H+][HS][H2S]
107=[0.3][HS][0.1] [[H+] from HCl = 0.3 and H2S would have dissociated negligibly]
[HS]=107×0.10.3=3.3×108M
Further Ka2=[H+][S2][HS]1.3×1013=[0.3][S2]3.3×108
[S2]=1.3×1013×3.3×1080.3=1.43×1020M

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