Question

A solution contains $25\%$ water, $50\%$ ethanoic acid and $25\%$ ethanol by mass. Compute the mole fraction of each component.

Answer 1

moles of water=$\frac{25}{18}=1.38$,

moles of ethanoic acid =$\frac{50}{60}=0.83$

moles of ethanol=$\frac{25}{46}=0.54$

moles fraction of water =$\frac{1.38}{1.38+0.83+0.54}$ =$\frac{1.38}{2.75}=0.50$

moles fraction of ethanoic acid =$\frac{0.83}{2.75}=0.30$

moles fraction of ethanol $=1-(0.5+0.3)=0.2$