A solution contains mixture of H2SO4 and H2C2O4-H2O- 25 mL of this solution requires 35-5 mL of N-10 NaOH for neutralization and 23-45 mL of N-10 KMnO4 for oxidation- Calculate the strength of H2C2O4 in g-L-

Let meq. of H_2SO_4 and H_2C_2O_4 be a and b respectively. #160;Acid base reaction of H_2SO_4 and H_2C_2O_4 with NaOH ...

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Standard XII

Chemistry

Stoichiometric Calculations

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Question

A solution contains mixture of $H_{2} S O_{4}$ and $H_{2} C_{2} O_{4} . H_{2} O$ . $25$ mL of this solution requires $35.5$ mL of $\frac{N}{10} N a O H$ for neutralization and $23.45$ mL of $\frac{N}{10} K M n O_{4}$ for oxidation. Calculate the strength of $H_{2} C_{2} O_{4}$ (in g/L).

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Solution

Let meq. of $H_{2} S O_{4}$ and $H_{2} C_{2} O_{4}$ be $a$ and $b$ respectively.
Acid-base reaction of $H_{2} S O_{4}$ and $H_{2} C_{2} O_{4}$ with $N a O H$ is taking place.
In $25$ mL solution:
$M e q . o f H_{2} S O_{4} + M e q . o f H_{2} C_{2} O_{4} = M e q . o f N a O H$
$a + b = 35.5 \times \frac{1}{10}$
or, $a + b = 3.55$ ......... (i)

Redox change of $H_{2} C_{2} O_{4}$ with $K M n O_{4}$ .
$M n^{7 +} + 5 e ⟶ M n^{2 +}$
$(C^{3 +})_{2} ⟶ 2 C^{4 +} + 2 e$
In $25$ mL solution:
$M e q . o f H_{2} C_{2} O_{4} = M e q . o f o x a l i c a c i d$
or, $b = 23.45 \times \frac{1}{10} = 2.345$ ........ (ii)

By equations (i) and (ii),
$M e q . o f H_{2} S O_{4} = a = 3.55 - 2.345 = 1.205$

$∴ N_{H_{2} S O_{4}} = \frac{1.205}{25} = 0.0482$

$∴$ Strength of $H_{2} S O_{4} = N \times E q . = 0.0482 \times 49$ $= 2.362$ g/L

$M e q . o f H_{2} C_{2} O_{4} = b = 2.345$

$∴ N_{H_{2} C_{2} O_{4}} = \frac{2.345}{25} = 0.0938$

$∴$ Strength of $H_{2} C_{2} O_{4} = 0.0938 \times 63 = 5.909$ g/L

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A solution contains mixture of H2SO4 and H2C2O4.H2O. 25 mL of this solution requires 35.5 mL of N10NaOH for neutralization and 23.45 mL of N10KMnO4 for oxidation. Calculate the strength of H2C2O4 (in g/L).

A solution contains mixture of $H_{2} S O_{4}$ and $H_{2} C_{2} O_{4} . H_{2} O$ . $25$ mL of this solution requires $35.5$ mL of $\frac{N}{10} N a O H$ for neutralization and $23.45$ mL of $\frac{N}{10} K M n O_{4}$ for oxidation. Calculate the strength of $H_{2} C_{2} O_{4}$ (in g/L).