A solution which is 10^-3 M each in Mn²⁺, Fe²⁺, Zn²⁺ and Hg²⁺ is treated with 10^-16 M sulphide ion. If K_sp of MnS, FeS, ZnS and HgS are 10^-15, 10^-23, 10^-20 and 10^-54 respectively, which one will precipitate first?

Q. A solution which is

10^{- 3} N

each in

M n^{2 +}, F e^{2 +}, Z n^{2 +}

and

H g^{2 +}

is treated with

10^{- 16} M

sulphide ion. If

K_{s p}

values of

M n S, F e S, Z n S

and

H g S

are

10^{- 15}, 10^{- 23}, 10^{- 20}

and

10^{- 54}

respectively, which one will precipitate first ?

Q. A solution which is

10^{- 3} M

each in

M n^{2 +}, F e^{2 +}, Z n^{2 +}

and

H g^{2 +}

is treated with

10^{- 16} M

sulphide ion. If

K_{s p}

of MnS,FeS,ZnS andHgS are

10^{- 15}, 10^{- 23}, 10^{- 20}

and

10^{- 54}

respectively, which one will precipitate first?

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A solution is 10−3M each in Mn2+,Fe2+,Zn2+ and Hg2+ is treated with 10−16M sulphide ion.If Ksp values of MnS, Fes, ZnS and HgS are 10−15,10−23,10−20 and 10−54 respectively, which one will precipitate first?

The correct option is C HgSThe salt with least solubility product Ksp will precipitate first⟹HgS[Ksp=10−54]

A solution is $10^{- 3} M$ each in $M n^{2 +}, F e^{2 +}, Z n^{2 +}$ and $H g^{2 +}$ is treated with $10^{- 16} M$ sulphide ion.If $K_{s p}$ values of MnS, Fes, ZnS and HgS are $10^{- 15}, 10^{- 23}, 10^{- 20}$ and $10^{- 54}$ respectively, which one will precipitate first?

The correct option is C HgS
The salt with least solubility product $K s p$ will precipitate first $⟹ H g S [K s p = 10^{- 54}]$