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Standard XII

Chemistry

Concentration Terms

A solution wh...

Question

A solution which is $10^{- 3} M$ each in $M n^{2 +}, F e^{2 +}, Z n^{2 +}$ and $H g^{2 +}$ is treated with $10^{- 16} M$ sulphide ion. If $K_{s p}$ of MnS,FeS,ZnS andHgS are $10^{- 15}, 10^{- 23}, 10^{- 20}$ and $10^{- 54}$ respectively, which one will precipitate first?

FeS

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MgS

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HgS

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ZnS

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Solution

The correct option is C HgS
Salt having low $K_{s p}$ precipitates first.
Thus $H g S$ will precipitate first.

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Similar questions

Q. A solution which is

10^{- 3} M

each in

{M n}^{2 +}, {F e}^{2 +}, {Z n}^{2 +}

and

{H g}^{2 +}

is treated with

10^{- 16} M

sulphide ion. if

K_{s p}

M n S, F e S, Z n S

and

H g S

are

10^{- 15}, 10^{- 23}, 10^{- 20}

and

10^{- 54}

respectively, which one will precipitate first?

Q. A solution is

10^{- 3} M

each in

M n^{2 +}, F e^{2 +}, Z n^{2 +}

and

H g^{2 +}

is treated with

10^{- 16} M

sulphide ion.If

K_{s p}

values of MnS, Fes, ZnS and HgS are

10^{- 15}, 10^{- 23}, 10^{- 20}

and

10^{- 54}

respectively, which one will precipitate first?

Q. A solution which is

10^{- 3} M

each in

M n^{2 +}, F e^{2 +}, Z n^{2 +}

, and

H g^{2 +}

is treated with

10^{- 16} M

sulphide ion. If the

K_{s p}

M n S, F e S, Z n S

and

H g S

are

10^{- 15}, 10^{- 23}, 10^{- 20}

and

10^{- 54}

respectively, which one will precipitate first?

A solution which is 10^-3 M each in Mn²⁺, Fe²⁺, Zn²⁺ and Hg²⁺ is treated with 10^-16 M sulphide ion. If K_sp of MnS, FeS, ZnS and HgS are 10^-15, 10^-23, 10^-20 and 10^-54 respectively, which one will precipitate first?

A solution which has $10^{- 3}$ M each of $M n^{2 +}, F e^{2 +}, Z n^{2 +}$ and $H g^{2 +}$ is treated with $10^{- 16}$ M sulphide ion. If $K_{s p}$ of $M n S$ , $F e S$ , $Z n S$ and $H g S$ are $10^{- 15}$ , $10^{- 23}$ , $10^{- 20}$ and $10^{- 54}$ respectively, which one will precipitate first?

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A solution which is 10−3M each in Mn2+,Fe2+,Zn2+ and Hg2+ is treated with 10−16M sulphide ion. If Ksp of MnS,FeS,ZnS andHgS are 10−15,10−23,10−20 and 10−54respectively, which one will precipitate first?

The correct option is C HgSSalt having low Ksp precipitates first.Thus HgS will precipitate first.

A solution which is $10^{- 3} M$ each in $M n^{2 +}, F e^{2 +}, Z n^{2 +}$ and $H g^{2 +}$ is treated with $10^{- 16} M$ sulphide ion. If $K_{s p}$ of MnS,FeS,ZnS andHgS are $10^{- 15}, 10^{- 23}, 10^{- 20}$ and $10^{- 54}$ respectively, which one will precipitate first?

The correct option is C HgS
Salt having low $K_{s p}$ precipitates first.
Thus $H g S$ will precipitate first.