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Standard XII

Chemistry

Solubility Product

A solution wh...

Question

A solution which has $10^{- 3}$ M each of $M n^{2 +}, F e^{2 +}, Z n^{2 +}$ and $H g^{2 +}$ is treated with $10^{- 16}$ M sulphide ion. If $K_{s p}$ of $M n S$ , $F e S$ , $Z n S$ and $H g S$ are $10^{- 15}$ , $10^{- 23}$ , $10^{- 20}$ and $10^{- 54}$ respectively, which one will precipitate first?

$F e S$

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$M g S$

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$H g S$

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$Z n S$

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Solution

The correct option is C
$H g S$

Since the solubility of $H g S$ is the least among the given options,so, it will get saturated first and will start precipitating.

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Similar questions

A solution which is 10^-3 M each in Mn²⁺, Fe²⁺, Zn²⁺ and Hg²⁺ is treated with 10^-16 M sulphide ion. If K_sp of MnS, FeS, ZnS and HgS are 10^-15, 10^-23, 10^-20 and 10^-54 respectively, which one will precipitate first?

Q. A solution which is

10^{- 3} N

each in

M n^{2 +}, F e^{2 +}, Z n^{2 +}

and

H g^{2 +}

is treated with

10^{- 16} M

sulphide ion. If

K_{s p}

values of

M n S, F e S, Z n S

and

H g S

are

10^{- 15}, 10^{- 23}, 10^{- 20}

and

10^{- 54}

respectively, which one will precipitate first ?

Q. A solution which is

10^{- 3} M

each in

M n^{2 +}, F e^{2 +}

and

H g^{2 +}

is treated with

10^{- 16} M

sulphide ion, If

K_{s p}

M n S, F e S, Z n S a n d H g S

are

10^{- 15}, 10^{- 25}, 10^{- 20}

and

10^{- 54}

respectively, which one will precipitate first?

Q. A solution which is

10^{- 3} M

each in

M n^{2 +}, F e^{2 +}, Z n^{2 +}

, and

H g^{2 +}

is treated with

10^{- 16} M

sulphide ion. If the

K_{s p}

M n S, F e S, Z n S

and

H g S

are

10^{- 15}, 10^{- 23}, 10^{- 20}

and

10^{- 54}

respectively, which one will precipitate first?

Q. A solution which is

10^{- 3} M

each in

{M n}^{2 +}, {F e}^{2 +}, {Z n}^{2 +}

and

{H g}^{2 +}

is treated with

10^{- 16} M

sulphide ion. if

K_{s p}

M n S, F e S, Z n S

and

H g S

are

10^{- 15}, 10^{- 23}, 10^{- 20}

and

10^{- 54}

respectively, which one will precipitate first?

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A solution which has 10−3 M each of Mn2+,Fe2+,Zn2+ and Hg2+ is treated with 10−16 M sulphide ion. If Ksp of MnS, FeS, ZnSand HgS are 10−15, 10−23, 10−20 and 10−54 respectively, which one will precipitate first?

The correct option is C HgS Since the solubility of HgS is the least among the given options,so, it will get saturated first and will start precipitating.

A solution which has $10^{- 3}$ M each of $M n^{2 +}, F e^{2 +}, Z n^{2 +}$ and $H g^{2 +}$ is treated with $10^{- 16}$ M sulphide ion. If $K_{s p}$ of $M n S$ , $F e S$ , $Z n S$ and $H g S$ are $10^{- 15}$ , $10^{- 23}$ , $10^{- 20}$ and $10^{- 54}$ respectively, which one will precipitate first?

The correct option is C
$H g S$

Since the solubility of $H g S$ is the least among the given options,so, it will get saturated first and will start precipitating.